General Guidelines to be Followed In Preparing BBS:
- The bars should be grouped together for each structural unit, e.g., beam, etc.
- In a building structure, the bars should be listed floor by floor
- For cutting and bending purposes, schedules should be provided as separate A4 sheets and not as part of the detailed reinforcement drawings.
- The form of bar and fabric schedule and the shapes of the bar used should be in accordance with BS 8666.
- It is preferable that bars should be listed in the schedule in numerical order.
- It is essential that the bar mark reference on the label attached to a bundle of bars refers uniquely to a particular group or set of bars of defined length, size, shape, and type used on the job.
- This is imperative as a bar mark reference can then point to a class of bar characteristics. Also, this helps steel fixers and laborers keep track of the type and number of bars needed to complete a certain work.
Bar Bending Schedule Required Ment Data
Estimation of steel quantity is an essential skill of any civil engineer. Every civil engineer must know the method of calculation of steel Calculation quantity from drawing.
Data requires for estimation of steel quantity:
1. Plan, Elevation & SectionÂ
Plan PDF FileÂ
2. Structural Detail (Slab & Beam)
Structural PDF File
3. All Dimensions Must be Clear and Co-Related.
Beam PDF File
How to Prepare a Slab BBS?Â
We calculated her two parts of caution of BBS as below
- Slab Beam.
- Slab.
Slab Beam Bar Bending ScheduleÂ
Slab Beam Location
Slab Beam Location PDF File
Here many beam shows. So we calculate TB1 Beam.
TB1 Beam.
Numbers of Bars for StirrupsÂ
Suppose the spacing of stirrups is 200 c/c and the length along which they are placed is 14100 mm, we can find the number of bars by the formula below
[ (14.100-200) / 200)] + 1 = 70.5 NosTotal Numer of Stirrups = 71 Nos
Stirrups Cutting Length
Cutting length beam stirrup
90 degree hook:
Length of stirrup = 2 (A + B) + 20 x diameter
135 degree hook:
Length of stirrup = 2 (A + B) + 24 x diameter
Length of stirrup = 2 ( (Length -2 Cover) + (Breadth-2 Cover) + 24 x diameter
diameter of Stirrups.
Length of stirrup = 2 (0.150 + 0.550) + 24 x 8
Length of stirrup = 1.592 m
Total Weight of Stirrups
Total Weight Stirrups = (No of ring x Cutting Length ) x (Weight diameter of bars)
Total Weight Stirrups = ( 71 x 1.592) x (0.395) = 44.648 kg
We must remember than steel is ductile in nature and is subject to elongation. Hence, the length of a bar is increased when bends or hooks are introduced. Hence, certain deductions are needed to offset this increase in length.
Cutting Length Bar:
Cutting Length = True Length of a bar – Deductions
For 45 degree
Cutting length  = Total length – 1 x Diameter of bar x No. of bends
Cutting length = (Total Length) +( 2 x L length) + (Lap Length (45 x d) ) – (2 x Bend) – (Cover)
Bottom BarÂ
2 nos bar 16 mm diameter
Cutting length = (11.400+2.400+0.200) + ( 2x 0.550) + ( 45 x 16) – ( 2 x 0.016 ) -(2 x 0.025)
Cutting length = (14.100) + (1.100) + (0.720) – (0.032) – (0.050)
Cutting length = 15.838 m
Total weight of bottom bar = No of Bars x Cutting length x Weight of bars
Total weight of bottom bar = 2 x 15.838 x 1.580 = 50.048 kg
Top Bar
2 nos bar 20 mm diameter
Cutting length = (11.400+2.400+0.200) + ( 2x 0.550) + ( 45 x 20) – ( 2 x 0.020 ) -(2 x 0.025)
Cutting length = (14.100) + (1.100) + (0.900) – (0.040) – (0.050)
Cutting length = 16.010 m
Total weight of top bar = No of Bars x Cutting length x Weight of bars
Total weight of top bar = 2 x 16.010 x 2.469 = 79.057 kg
Total Weight of Beam = Total Weight Stirrups + Total weight of bottom bar + Total weight of top bar
Total Weight of Beam = 44.648 kg + 50.048 kg + 79.057 kg = 173.753 kgÂ
Slab Bar Bending Schedule Excel Sheet
Cutting Length Slab Bar
Cutting Length of Bar = (Total length) + ( Bentup Bar Length (0.42 x d)) +Lap
Area ( -1 to 3)/(-A to +B)
For X Direction
8 mm Diameter 200 mm c/c
No of Bars = (7 /0.2) + 1 = 36.0 Nos. = 36 Nos
Cutting Bar = (0.100+2.400+4.300+1.000+2.800+1.000+0.100) +( 0.42 * (0.125-0.025-0.025)) + 0
Cutting Bar = (11.700) + (0.032)Â = 11.732 m
Total weight of X direction slab bar = No of Bars x Cutting length x Weight of bars
Total weight of X direction slab bar = 36 x 11.732 x 0.395 = 166.829 kg
For Y Direction
8 mm Diameter 200 mm c/c
No of Bars = (11.700/0.200) + 1 = 59.5 Nos. = 60 Nos
Cutting Bar = (0.100+1.800+3.200+1.800+0.100) +( 0.42 * (0.125-0.025-0.025)) + 0
Cutting Bar = (7.000) + (0.0315)Â = 7.032 m
Total weight of Y direction slab bar = No of Bars x Cutting length x Weight of bars
Total weight of Y direction slab bar = 60 x 7.032 x 0.395 = 166.658 kg
Extra BarsÂ
10 mm Diameter 200 mm c/c
No of Bars = (11.700/0.200) + 1 = 59.5 Nos. = 60 Nos
TB2 area A/( – 1 to +3) =Â (0.500 + 0.200 + 0.900 ) = 1.600 m
Total weight of TB1 = No of Bars x Cutting length x Weight of Diameter bar
Total weight of TB1 = 60 x 1.600 x 0.616 = 59.136 kgÂ
No of Bars = (7 /0.2) + 1 = 36.0 Nos. = 36 Nos
TB3 area 4 (-A to +B) =Â (0.700 + 0.200 + 1.250 ) = 2.150 mÂ
Total weight of TB3 = 36 x 2.150 x 0.616 = 47.678 kgÂ
No of Bars = (7 /0.2) + 1 = 36.0 Nos. = 36 Nos
TB5 area 1/2 (-A to +B) =Â (1.250 + 0.200 + 1.400 ) = 2.850 m
Total weight of TB5 = 36 x 2.850 x 0.616 = 63.202 kgÂ
Total weight of Slab = Total weight of X direction slab bar + Total weight of Y direction slab bar + Total weight of TB1 + Total weight of TB3 + Total weight of TB5
Total weight of Slab = 166.829 kg + 166.658 kg + 59.136 kg + 47.678 kg + 63.202 kg = 503.03 kgÂ
How to Calculate Slab Steel Quantity from Drawing Excel Sheet
How to Calculate Slab Steel Quantity from Drawing Excel Sheet Click Here
Bar Bending Schedule for Slab
| S.NO. | Description | Shape Of Bar | Grid | No of Column | Nos. of Bar | Length | Dia. Of Bar | Dia Wise Length In Mtr. | Total Weight In KG | ||||||||
| 8 mm | 10 mm | 12 mm | 16 mm | 20 mm | 25 mm | Sub Total | Cumulative | ||||||||||
| 0.395 | 0.616 | 0.888 | 1.579 | 2.466 | 3.854 | ||||||||||||
| A | Slab Beam |  |
|||||||||||||||
| 1 | TB1 ( 200 X 600 ) | ||||||||||||||||
| -A / (-1 to +3) | |||||||||||||||||
| +B / (-1 to +3) | |||||||||||||||||
| Top Bar | 2 | 2 | 15.200 | 20 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â 60.80 | Â Â Â Â Â Â Â Â Â – | |||||||
| Bottom Bar | 2 | 2 | 15.200 | 16 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 60.80 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | |||||||
| Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | ||||||||||||
| Lap |  |
||||||||||||||||
| Top Bar | 2 | 2 | 1 | 20 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4 | Â Â Â Â Â Â Â Â Â – | |||||||
| Bottom Bar | 2 | 2 | 0.8 | 16 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â 3.20 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | |||||||
| Ring | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | |||||||||||
| 200 C/C ( -1 to 3) | 2 | 55 | 1.560 | 8 | Â Â Â Â Â Â Â Â Â 171.60 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | |||||||
| 150 C/C ( 3 to+ 3) | 2 | 16 | 1.560 | 8 | Â Â Â Â Â Â Â Â Â Â Â Â 49.92 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â Â – | |||||||
| Total Length as per dia | Â Â Â Â Â Â 221.52 | Â Â Â Â Â Â Â Â Â Â – | Â Â Â Â Â Â – | Â Â Â Â Â Â Â Â 64.00 | Â Â Â Â 64.80 | Â Â Â Â Â Â – | |||||||||||
| Dia in K.g/m | 0.395 | 0.616 | 0.888 | 1.579 | 2.466 | 3.854 | |||||||||||
| Total weight as per dia | 87.5 | 0 | 0 | 101.056 | 159.797 | 0 | 348.353 | ||||||||||
| Total Qty in K.g | 348.353 kg | ||||||||||||||||
Frequently asked questions (FAQs) that could be included in your article on Bar Bending Schedule (BBS) preparation for building structures:
What is a Bar Bending Schedule (BBS)?
A Bar Bending Schedule (BBS) is a detailed report that provides information about the reinforcement steel bars (rebars) to be used in the construction of a structure. It includes bar shapes, quantities, dimensions, and bending details.
Why is a Bar Bending Schedule important in construction?
A BBS is crucial for ensuring accurate procurement, cutting, bending, and placement of reinforcement bars according to structural drawings. It helps in minimizing wastage, ensuring structural integrity, and maintaining construction timelines.
What information does a Bar Bending Schedule include?
A typical BBS includes details such as bar mark (identification number), bar shape and size, cutting lengths, bending shapes and dimensions, quantities, and weights of reinforcement bars required for each structural element.
How is a Bar Bending Schedule prepared?
Preparation involves analyzing structural drawings (plans, elevations, and sections), calculating quantities of rebars required based on design specifications (spacing, overlaps, lap lengths), and documenting these details in a systematic format using industry standards like BS 8666.
What are the benefits of following BBS guidelines?
Following BBS guidelines ensures consistency in reinforcement placement, reduces errors during construction, facilitates efficient material procurement, and supports quality control and structural safety compliance.
What are the common challenges in preparing a Bar Bending Schedule?
Challenges include interpreting complex structural drawings accurately, calculating precise cutting and bending lengths, coordinating with design changes, and ensuring compliance with local building codes and standards.
Can BBS be prepared manually or digitally?
BBS can be prepared manually using spreadsheets or dedicated software tools designed for structural detailing and reinforcement calculations. Digital tools offer advantages in terms of accuracy, efficiency, and integration with Building Information Modeling (BIM) systems.
How does BBS contribute to cost estimation and project management?
BBS provides accurate data for cost estimation of reinforcement materials, labor requirements for cutting and bending, and helps in project scheduling by ensuring timely availability of required materials at construction sites.
Who is responsible for preparing and reviewing the Bar Bending Schedule?
Civil engineers, structural designers, and steel detailers typically prepare BBS under the supervision of project managers or senior engineers. Reviewing involves cross-checking BBS against structural design drawings to ensure accuracy and compliance.
How does BBS support sustainability in construction practices?
By minimizing material wastage and optimizing reinforcement placement, BBS contributes to sustainable construction practices by reducing environmental impact and conserving resources.
